Difference between revisions of "Production Potential"
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[[Production Potential]] is the '''maximum''' rate that can be delivered by [[Well]], [[Pattern]], [[Block]] or [[Reservoirs | Reservoir]]. | [[Production Potential]] is the '''maximum''' rate that can be delivered by [[Well]], [[Pattern]], [[Block]] or [[Reservoirs | Reservoir]]. | ||
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| + | [[File:Production Potental.png| Production Potential]] | ||
==Math and Physics== | ==Math and Physics== | ||
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The rate <math>Q</math> is '''maximum''' then <math>\Delta P</math> and <math>J_D</math> are '''maximum'''. | The rate <math>Q</math> is '''maximum''' then <math>\Delta P</math> and <math>J_D</math> are '''maximum'''. | ||
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==Maximum <math>\Delta P</math>== | ==Maximum <math>\Delta P</math>== | ||
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<math>\Delta P= \bar P_r - P_{wf}</math> | <math>\Delta P= \bar P_r - P_{wf}</math> | ||
| − | The maximum drawdown is reached then the flowing bottomhole pressure, <math>P_{wf} | + | The maximum drawdown is reached then the flowing bottomhole pressure, <math>P_{wf} = 0</math>, so: |
<math>{\Delta P}_{max}= P_r</math> | <math>{\Delta P}_{max}= P_r</math> | ||
==Maximum <math>J_D</math>== | ==Maximum <math>J_D</math>== | ||
| + | The unstimulated vertical well potential in a pseudo steady radial flow is: | ||
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| + | :<math> {J_D}_{max} \approx \frac{1}{ln{\frac{500}{0.1}-\frac{3}{4}+0}} \approx 0.13</math> | ||
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| + | The maximum possible stimulated well potential for pseudo steady linear flow is: | ||
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| + | <math>{J_D}_{max}= \frac{6}{\pi} \approx 1.91 </math> , see [[6/π stimulated well potential]] | ||
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| + | The maximum possible stimulated well potential for steady state linear flow is: | ||
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| + | <math>{J_D}_{max}= \frac{4}{\pi} \approx 1.27 </math> , see [[4/π stimulated well potential]] | ||
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| + | ==Achieving potential== | ||
| + | Can [[Production Potential]] be achieved? | ||
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| + | The ideal, of producing and recovering at potential, is rarely obtained in practice. [[29+ reasons why you can not increase the production |Reasons]] for this vary from company to company, but more often than not, the reason is [[Production Potential]] is not known and therefore not managed<ref name=DW />. | ||
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| + | Calculating the [[Production Potential]] opens the pathway to achieve potential. | ||
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| + | ==See also== | ||
| + | [[JD]]<BR/> | ||
| + | [[6/π stimulated well potential]]<BR/> | ||
| + | [[4/π stimulated well potential]]<BR/> | ||
== References == | == References == | ||
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[[Category:Enhancement List]] | [[Category:Enhancement List]] | ||
[[Category:E&P Portal]] | [[Category:E&P Portal]] | ||
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| + | {{#seo: | ||
| + | |title=Production Potential | ||
| + | |titlemode= replace | ||
| + | |keywords=production potential, oil and gas production, oil production, oil and gas production optimization | ||
| + | |description=Production Potential is the maximum rate that can be delivered through oil and gas production optimization | ||
| + | }} | ||
Latest revision as of 18:45, 8 July 2023
Contents
Brief
Production Potential is the maximum rate that can be delivered by Well, Pattern, Block or Reservoir.
Math and Physics
The Darcy's law can be written as:
where:
is the oil or gas production rate,
is the Reservoir transmissibility and is given by the Mother Nature,
is the Lift System Drawdawn which is set by the operational engineering practices[1],
is the Completion System dimensionless productivity index which is set by the design engineering practices[1].
The rate is maximum then and are maximum.
Maximum
The drawdown is:
The maximum drawdown is reached then the flowing bottomhole pressure, 
, so:
Maximum
The unstimulated vertical well potential in a pseudo steady radial flow is:
The maximum possible stimulated well potential for pseudo steady linear flow is:
, see 6/π stimulated well potential
The maximum possible stimulated well potential for steady state linear flow is:
, see 4/π stimulated well potential
Achieving potential
Can Production Potential be achieved?
The ideal, of producing and recovering at potential, is rarely obtained in practice. Reasons for this vary from company to company, but more often than not, the reason is Production Potential is not known and therefore not managed[1].
Calculating the Production Potential opens the pathway to achieve potential.
See also
JD
6/π stimulated well potential
4/π stimulated well potential
References
- ↑ 1.0 1.1 1.2
Wolcott, Don (2009). Applied Waterflood Field Development
. Houston: Energy Tribune Publishing Inc.
