Difference between revisions of "Water density"

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The density of formation water (brine) at reservoir conditions <ref name= M1990/>
 
The density of formation water (brine) at reservoir conditions <ref name= M1990/>
  
:<math> \rho_{wR}=1/B_w </math>
+
:<math> \rho_{wR}=\rho_{wSC}/B_w </math>
  
 
==Example. Calculating formation water density ==
 
==Example. Calculating formation water density ==
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===Input data===
 
===Input data===
 
:<math> C_{mg/l} = 74289.3 </math>
 
:<math> C_{mg/l} = 74289.3 </math>
 +
:<math> B_w = 1.022 </math> at 3176 psia and 165°F
  
 
Estimate the density of the brine at standard conditions (14.7psia & 60°F) and at 3176 psia and 165°F?  
 
Estimate the density of the brine at standard conditions (14.7psia & 60°F) and at 3176 psia and 165°F?  
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===Solution===
 
===Solution===
 
:<math> \rho_{wSC} = 74289.3/25000 + 62.428 = 65.4 lb_m/ft^3</math>
 
:<math> \rho_{wSC} = 74289.3/25000 + 62.428 = 65.4 lb_m/ft^3</math>
 +
:<math> \rho_{wR} = 65.4/1.022=  64 lb_m/ft^3</math>
  
 
== Nomenclature  ==
 
== Nomenclature  ==

Revision as of 12:12, 1 October 2020

Water density

Water density

The density of formation water (brine) at standard conditions (14.7psia & 60°F)[1]

 \rho_{wSC} = C_{mg/l}/25000 + 62.428

The density of formation water (brine) at reservoir conditions [1]

 \rho_{wR}=\rho_{wSC}/B_w

Example. Calculating formation water density

Example source [1]

Input data

 C_{mg/l} = 74289.3
 B_w = 1.022 at 3176 psia and 165°F

Estimate the density of the brine at standard conditions (14.7psia & 60°F) and at 3176 psia and 165°F?

Solution

 \rho_{wSC} = 74289.3/25000 + 62.428 = 65.4 lb_m/ft^3
 \rho_{wR} = 65.4/1.022=  64 lb_m/ft^3

Nomenclature

 B_w = water formation volume factor, res bbl/STB
 C_{mg/l} = water salinity or solids concentration, mg/l
 \rho_{wSC} = water density at standard conditions, lbm/ft3

See also

Water solids concentration

References

  1. 1.0 1.1 1.2 McCain, W.D. Jr. (1990). Properties of Petroleum Fluids (2 ed.). Oklahoma: PennWell Corp. ISBN 978-0878143351. 

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