Difference between revisions of "Reservoir simulator benchmark tests"

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Before running any 3D reservoir simulator for a full scale field history matching or forecasts it is a good practice to make sure that the simulator is performing well on a simple benchmark tests with the well known analytical solutions.
 
Before running any 3D reservoir simulator for a full scale field history matching or forecasts it is a good practice to make sure that the simulator is performing well on a simple benchmark tests with the well known analytical solutions.
  
By running those cases you could get ahead of the learning curve and gain confidence in your simulation results.
+
By running those cases you could get ahead of the learning curve and gain confidence in your simulation results.
  
 
==Calculating well potential==
 
==Calculating well potential==

Revision as of 13:08, 12 July 2023

Brief

Before running any 3D reservoir simulator for a full scale field history matching or forecasts it is a good practice to make sure that the simulator is performing well on a simple benchmark tests with the well known analytical solutions.

By running those cases you could get ahead of the learning curve and gain confidence in your simulation results.

Calculating well potential

Analytical equations are available to calculate the flow rate potential for unstimulated and stimulated wells. Steady state and pseudo steady state flow regimes are considered.

Simulation Runs

Now let's attach the infinite aquifer to the can of gas and run scenarios:

  1. Slow - choked gas rate
  2. Fast - 2x enhanced gas rate

Slow Fast

Oh no, water killed the well quick in the "Fast" case! We told you what! Right, but … which case produced more gas?

Gas Recovery

Gas Recovery Results

12% more recovery with the enhanced production over 20 years. Why?

Because of the pressure! The lower the reservoir pressure the more gas is produced before the water hits the perfs. It’s just physics!

Reservoir Pressure

Math and Physics

According to the Boyle's law (1662):

 PV = constant

where P is pressure, V is volume.

In our case

 PV = constant = P_1V_1 = P_2V_2=P_{res}V_{res}

The gas produced volume of the "Slow case"

 V_1 = \frac{P_{res}V_{res}}{P_1}

The gas produced volume of the "Fast case"

 V_2 = \frac{P_{res}V_{res}}{P_2}

And V2 > V1 because P2 < P1. The lower the P2 gets over P1 the higher the incremental recovery will be.

Summary

Produce gas reservoirs fast to increases recoveries.

If you have an aquifer you have to produce fast.

If you don’t have an aquifer…, so you don’t have water to complain.

Video

Watch our video explaining the gas reservoir production using the Can Of Beans (Gas) as an example

Watch on youtube

Model overview

Simulation model

  • Cylindrical grid (10x10x30)
  • re=500m, rw=0.1m, h=30m
  • kx=ky=5mD, kz/kx=0.1, phi=0.2
  • Pi=300bar, hres=3000m
  • Gas and water PVT model
  • SGgas=0.58
  • Aquifer at the bottom (CT infinite extent)
  • qgas_slow = 100 000 m3/d
  • qgas_fast = 200 000 m3/d

3D reservoir simulation software

  • ECLIPSE
  • tNavigator
  • CMG
  • Waiwera

See also

References

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By Mikhail Tuzovskiy on 20230712130836