Difference between revisions of "Water formation volume factor"

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(Math and Physics)
(Math and Physics)
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:<math> B_w = (1+\Delta V_{wp})(1+\Delta V_{wT})</math>
 
:<math> B_w = (1+\Delta V_{wp})(1+\Delta V_{wT})</math>
 +
 +
where
 +
 +
:<math> \Delta V_{wp} = -1.95301e-9 P T - 1.72834e-13 P^2 T - 3.58922e-7 P - 2.25341e-10 P^2</math>
 +
 +
$dvwp = -1.95301e-9 * $psi * $F - 1.72834e-13 * pow($psi, 2) * $F - 3.58922e-7 * $psi - 2.25341e-10 * pow($psi, 2);
 +
$dvwt = -1.0001e-2 + 1.33391e-4 * $F + 5.50654e-7 * pow($F, 2);
  
 
==Example. Calculating water salinity from density==
 
==Example. Calculating water salinity from density==

Revision as of 05:50, 1 October 2020

Water formation volume factor

The water formation volume factor represents the change in volume of the brine as it is transported from the reservoir conditions to surface conditions[1].

The units are reservoir barrels per surface barrel at standard conditions, res bbl/STB.

Water formation volume factor

Math and Physics

 B_w = (1+\Delta V_{wp})(1+\Delta V_{wT})

where

 \Delta V_{wp} = -1.95301e-9 P T - 1.72834e-13 P^2 T - 3.58922e-7 P - 2.25341e-10 P^2

$dvwp = -1.95301e-9 * $psi * $F - 1.72834e-13 * pow($psi, 2) * $F - 3.58922e-7 * $psi - 2.25341e-10 * pow($psi, 2); $dvwt = -1.0001e-2 + 1.33391e-4 * $F + 5.50654e-7 * pow($F, 2);

Example. Calculating water salinity from density

Example source [1]

Input data

\rho_w = 65.4 lbm/ft3

Calculate water salinity in weight percent solids?

Solution

 SG_w = \rho_w/62.428=1.0476
 C_{mg/l} = 25000 (1.0476 - 1) 62.428 = 74289.32
 C_{ppm} = 74289.32 / 1.0476 = 70913.8
 C_W = 70913.8 / 10000 = 7.1 %

Nomenclature

 C_{ppm} = water salinity / solids concentration, ppm
 C_{mg/l} = water salinity / solids concentration, mg/l
 C_W = weight percent solids, %
 SG_w = water specific gravity, dimensionless

See also

Water solids concentration

References

  1. 1.0 1.1 McCain, W.D. Jr. (1990). Properties of Petroleum Fluids (2 ed.). Oklahoma: PennWell Corp. ISBN 978-0878143351.