Difference between revisions of "4/π stimulated well potential"

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(Math & Physics)
(Math & Physics)
Line 8: Line 8:
 
Steady state flow boundary conditions:
 
Steady state flow boundary conditions:
  
<math>P |_{x=x_e/2} = P |_{x=-x_e/2} = P_i</math>
+
:<math>P |_{x=x_e/2} = P |_{x=-x_e/2} = P_i</math>
  
<math> \frac{dp}{dt} =0\ for \ \forall x </math>
+
:<math> \frac{dp}{dt} =0\ for \ \forall x </math>
  
 
From [[Darcy's law]]:
 
From [[Darcy's law]]:
  
<math>\frac{q}{2}=\frac{kA}{B \mu}\ \frac{dP}{dx}</math>
+
:<math>\frac{q}{2}=\frac{kA}{B \mu}\ \frac{dP}{dx}</math>
 +
 
 +
:<math> A =y_e\*h</math>
 +
 
  
  

Revision as of 09:34, 10 September 2018

Brief

Stimulated well drainage

4/π is the maximum possible stimulation potential for steady state linear flow in a square well spacing.

Math & Physics

Steady state flow boundary conditions:

P |_{x=x_e/2} = P |_{x=-x_e/2} = P_i
 \frac{dp}{dt} =0\ for \ \forall x

From Darcy's law:

\frac{q}{2}=\frac{kA}{B \mu}\ \frac{dP}{dx}
Failed to parse (lexing error): A =y_e\*h