18.41 derivation - Revision history

MishaT at 09:32, 12 July 2023

2023-07-12T09:32:45Z

2023-07-09T10:44:00Z

2023-07-09T10:40:59Z

2023-07-09T10:40:10Z

‎Math and Physics

2023-07-09T10:38:36Z

‎Nomenclature

2023-07-09T10:37:16Z

‎See Also

2023-07-09T10:36:44Z

‎Math and Physics

2023-07-09T10:34:29Z

‎Math and Physics

2023-07-09T10:32:54Z

‎Math and Physics

2023-07-09T10:32:04Z

‎Math and Physics

← Older revision		Revision as of 09:32, 12 July 2023
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	\|description=18.41 is the well know constant which is used for converting from the Darcy's law units to the metric units in the well's inflow equations.		\|description=18.41 is the well know constant which is used for converting from the Darcy's law units to the metric units in the well's inflow equations.
	}}		}}
		+	<div style='text-align: right;'>By Mikhail Tuzovskiy on {{REVISIONTIMESTAMP}}</div>

@@ Line 41: / Line 41: @@
 Note that the published<ref name=DW/> and commonly used constant in '''18.41'''.
 == Nomenclature  ==
@@ Line 67: / Line 62: @@
 :<math> \mu </math> = [[Darcy's law]] oil viscosity, cp
 :<math> \mu_o </math> = oil viscosity, cp
 ==References==

@@ Line 40: / Line 40: @@
 :<math> C_{RF} =  \frac{C_{LF}}{2\pi} = \frac{115.7407407}{2\pi} = 18.42 </math>
-Note that the commonly published and used constant in 18.41
+Note that the published<ref name=DW/> and commonly used constant in '''18.41'''.
 ==See Also==

← Older revision		Revision as of 10:40, 9 July 2023
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	:<math> C_{RF} = \frac{C_{LF}}{2\pi} = \frac{115.7407407}{2\pi} = 18.42 </math>		:<math> C_{RF} = \frac{C_{LF}}{2\pi} = \frac{115.7407407}{2\pi} = 18.42 </math>
		+
		+	Note that the commonly published and used constant in 18.41

	==See Also==		==See Also==

@@ Line 48: / Line 48: @@
 :<math> A </math> = [[Darcy's law]] cross-sectional area, cm<sup>2</sup>
-:<math> B_o </math> = oil formation volume factor, bbl/stb
+:<math> B_o </math> = oil formation volume factor, m^3/m^3
 :<math> C_{LF} </math> = linear flow units conversion constant
 :<math> C_{RF} </math> = radial flow units conversion constant
-:<math> h</math> = effective feet of oil pay, ft
+:<math> h</math> = effective feet of oil pay, m
 :<math> J_D </math> = dimensionless productivity index, dimensionless
 :<math> k</math> = [[Darcy's law]] permeability, d
@@ Line 57: / Line 57: @@
 :<math> L </math> = [[Darcy's law]] length, cm
 :<math> P </math> = [[Darcy's law]] pressure, atm
-:<math> \Delta P </math> = drawdown, psia
+:<math> \Delta P </math> = drawdown, atm
 :<math> q </math> = [[Darcy's law]] flow rate, cm<sup>3</sup>/sec
-:<math> q_o </math> = oil flow rate, stb/d
+:<math> q_o </math> = oil flow rate, m^3/d
 ===Greek symbols===

@@ Line 42: / Line 42: @@
 ==See Also==
 [[Darcy's law]]<BR/>
-[[141.2 derivation]]
+[[141.2 derivation]]<BR/>
 [[18.41 derivation]]

@@ Line 34: / Line 34: @@
 where
-:<math> C_{LF} = \frac{1000 \times 100}{10000} \frac{1000000}{86400} = \frac{1000\ 14.695950253959\ 30.48^2\ 5.61458333}{86400} = 887.2201322</math>
+:<math> C_{LF} = \frac{1000 \times 100}{10000} \frac{1000000}{86400} = \frac{10000000}{86400} = 115.7407407</math>
 For the radial flow:
-:<math> C_{RF} =  \frac{C_{LF}}{2\pi} = \frac{887.2201322}{2\pi} = 141.20546964</math>
+:<math> C_{RF} =  \frac{C_{LF}}{2\pi} = \frac{115.7407407}{2\pi} = 18.42 </math>
 ==See Also==

@@ Line 30: / Line 30: @@
 And:
-:<math> \frac{[bbl]}{[day]} = - C_{LF} \frac{[mD][ft^2]}{[cP]} \frac{[psia]}{[ft]}</math>
+:<math> \frac{[m^3]}{[day]} = - C_{LF} \frac{[mD][m^2]}{[cP]} \frac{[atm]}{[m]}</math>
 where
-:<math> C_{LF} = \frac{1000\ 14.695950253959}{30.48} \frac{30.48^3\ 5.61458333}{86400} = \frac{1000\ 14.695950253959\ 30.48^2\ 5.61458333}{86400} = 887.2201322</math>
+:<math> C_{LF} = \frac{1000 \times 100}{10000} \frac{1000000}{86400} = \frac{1000\ 14.695950253959\ 30.48^2\ 5.61458333}{86400} = 887.2201322</math>
 For the radial flow:

@@ Line 26: / Line 26: @@
 So:
-:<math> \frac{[m^3]}{[day]} \frac{86400}{1000000} = - \frac{[mD][m^2]}{[cP]} \frac{[atm]}{[m]} \frac{1000\ 100}{10000}</math>
+:<math> \frac{[m^3]}{[day]} \frac{86400}{1000000} = - \frac{[mD][m^2]}{[cP]} \frac{[atm]}{[m]} \frac{1000 \times 100}{10000}</math>
 And: